The Nernst formulation of the third law of ordinary thermodynamics (of
ten referred to as the ''Nernst theorem'') asserts that the entropy S
of a system must go to zero (or a ''universal constant'') as its tempe
rature T goes to zero. This assertion is commonly considered to be a f
undamental law of thermodynamics. As such, it seems to spoil the other
wise perfect analogy between the ordinary laws of thermodynamics and t
he laws of black hole mechanics, since rotating black holes in general
relativity do not satisfy the analogue of the ''Nernst theorem.'' The
main purpose of this paper is to attempt to lay to rest the ''Nernst
theorem'' as a law of thermodynamics. We consider a boson (or fermion)
ideal gas with its total angular momentum J as an additional state pa
rameter, and we analyze the conditions on the single-particle density
of states, g(epsilon,j), needed for the Nernst formulation of the thir
d law to hold. (Here, epsilon and j denote the single-particle energy
and angular momentum.) Although it is shown that the Nernst formulatio
n of the third law does indeed hold under a wide range of conditions,
some simple classes of examples of densities of states which violate t
he ''Nernst theorem'' are given. In particular, at zero temperature, a
boson (or fermion) gas confined to a circular string (whose energy is
proportional to its length) not only violates the ''Nernst theorem''
also but reproduces some other thermodynamic properties of an extremal
rotating black hole. [S0556-2821(97)01122-3].