WHY PENTAPHOSPHOLE, P5H, IS PLANAR IN CONTRAST TO PHOSPHOLE, (CH)(4)PH

Citation
Mn. Glukhovtsev et al., WHY PENTAPHOSPHOLE, P5H, IS PLANAR IN CONTRAST TO PHOSPHOLE, (CH)(4)PH, Journal of physical chemistry, 100(32), 1996, pp. 13447-13454
Citations number
67
Categorie Soggetti
Chemistry Physical
ISSN journal
00223654
Volume
100
Issue
32
Year of publication
1996
Pages
13447 - 13454
Database
ISI
SICI code
0022-3654(1996)100:32<13447:WPPIPI>2.0.ZU;2-O
Abstract
In contrast to phosphole, (CH)(4)PH, pentaphosphole, P5H, has a planar C-2 upsilon minimum, At RMP2(fc)/6-31G + ZPE(RMP2(fc)/6-31G*//RMP2(f c)/6-31G) the aromatic stabilization energy (ASE) of P5H (17 kcal/mol ) is larger than of (CH)(4)PH (ASE = 7 kcal/mol) but smaller than of ( CH)(4)NH (25.5 kcal/mol) and N5H (29 kcal/mol), However, pentaphosphol e is thermodynamically stable by 58.2 kcal/mol (54.7 kcal/mol, MP4SDTQ (fc)/6-3 1G//MP2(fc)/6-31G* + ZPE(RHF/6-31G*)) toward dissociation in to PPPH and P-2. Other P5H isomers have relative energies of 9 (tricyc lic, C-s), 17.4 (bicyclic, C-s), 25.6 (monocyclic, P-3-P=PH, C-s), and 53.5 (open chain, PPPPPH, C-1) kcal/mol. Due to its electropositive c haracter, the -PH2 substituent reduces the inversion barrier of tricoo rdinate phosphorus, Delta E(inv)(P), from 35 kcal/mol for PH3 to 20.3 kcal/mol for HP(PH2)(2) and 16.1 for P(PH2)(3). In addition, pi conjug ation of -P=PH substituents reduce Delta E(inv)(P) further to 13.5 in HP(P=PH)(2) and 6.1 kcal/mol in P(P=PH)(3). In contrast, the vinyl gro ups in HP(CH=CH2)(2) and P(CH=CH2)(3) reduce the inversion barriers on ly to 31.4 and 27.8 kcal/mol, respectively. Consequently, in P5H and i ts derivatives endocyclic electronegativity effects together with arom aticity of the P-5 ring eliminate the inversion barriers, Other bondin g types favoring planar tricoordinate phosphorus are described (includ ing a bicyclic P-8 isomer with two P-5 rings only 18.4 kcal/mol higher in energy than two P-4 molecules).