SYNTHESIS AND CHARACTERIZATION OF [YB(NH3)(8)][CU(S-4)(2)].NH3, [YB(NH3)(8)][AG(S-4)(2)].2NH3, AND [LA(NH3)9][CU(S4)2] IN SUPERCRITICAL AMMONIA - METAL SULFIDE SALTS OF THE FIRST HOMOLEPTIC LANTHANIDE AMINE COMPLEXES

Citation
Dm. Young et al., SYNTHESIS AND CHARACTERIZATION OF [YB(NH3)(8)][CU(S-4)(2)].NH3, [YB(NH3)(8)][AG(S-4)(2)].2NH3, AND [LA(NH3)9][CU(S4)2] IN SUPERCRITICAL AMMONIA - METAL SULFIDE SALTS OF THE FIRST HOMOLEPTIC LANTHANIDE AMINE COMPLEXES, Inorganic chemistry, 35(26), 1996, pp. 7620-7625
Citations number
31
Categorie Soggetti
Chemistry Inorganic & Nuclear
Journal title
ISSN journal
00201669
Volume
35
Issue
26
Year of publication
1996
Pages
7620 - 7625
Database
ISI
SICI code
0020-1669(1996)35:26<7620:SACO[[>2.0.ZU;2-K
Abstract
Three new lanthanide metal polysulfides have been synthesized in super critical ammonia: [Yb(NH3)(8)][Cu(S-4)(2)]. NH3 (I), [Yb(NH3)(8)][Ag(S -4)(2)]. 2NH(3) (II), [La(NH3)](9)[CU(S-4)2] (III). Compounds were pre pared in sealed quartz tubes which were filled to one-third volume wit h liquid ammonia and heated at 170 degrees C for 3 days. Compounds I a nd II were obtained from the reaction of a premade ytterbium polysulfi de with M and S in the ratio of 1:1:4, while [La(NH3)(9)][Cu(S-4)(2)], III, was Obtained by reacting La, Cu, and S in the ratio of 1:1:8. In all these compounds, the lanthanide cation is coordinated only by amm onia, while the M(+) is chelated by S-4(2-) to form metal tetrasulfide rings. [Yb(NH3)(8)][Cu(S-4)(2)]. NH3 and [Yb(NH3)(8)][Ag(S-4)(2)]. 2N H(3) contain [M(S-4)(2)](3-) anionic units with M(+) in a distorted te trahedral coordination environment chelated by two S-4(2-) groups. Com pound III, [La(NH3)(9)][Cu(S-4)(2)], also contains anionic [Cu(S-4)(2) ](3-) units; however, Cu+ is in a trigonal planar coordination geometr y due;to the presence of one monodentate S-4(2-). All the compounds ar e unstable with respect to loss of ammonia, and decomposition yielded known ternary and binary phases. Crystallographic data for the compoun ds are the following: I, space group = <I(4)over bar>, Z = 2, a = 10.0 24(4) Angstrom, c = 9.753,(4) Angstrom; II, space group = P2(1)2(1)2(1 ), Z = 4, a = 11.177(4) Angstrom, b = 20.472(6) Angstrom, c = 9.754(3) Angstrom; III, space group = P2(1)/n, Z = 4, a = 9.891(2) Angstrom, b = 12.600(3) Angstrom, c = 17.812(3) Angstrom, beta = 103.57(2)degrees .