Let A and C be m-by-n complex matrices, and let B and D be n-by-m comp
lex matrices. The pair (A, B) is cantragrediently equivalent to the pa
ir (C, D) if there are square nonsingular complex matrices X and Y suc
h that XAY(-1)=C and YBX(-1)=D. Contragredient equivalence is a common
generalization of four basic equivalence relations: similarity, consi
milarity, complex orthogonal equivalence, and unitary equivalence. We
develop a complete set of invariants and an explicit canonical form fo
r contragredient equivalence and show that (A, A(T)) is contragedientl
y equivalent to (C, C-T) if and only if there are complex orthogonal m
atrices P and Q such that C=PAQ. Using this result, we show that the f
ollowing are equivalent for a given n-by-n complex matrix A: (1) A=QS
for some complex orthogonal Q and some complex symmetric S; (2) A(T)A
is similar to AA(T); (3) (A, A(T)) is contragrediently equivalent to (
A(T), A); (4) A = Q(1)A(T)Q(2) for some complex orthogonal Q(1), Q(2);
(5) A = PA(T)P for some complex orthogonal P. We then consider a line
ar operator phi on n-by-n complex matrices that shares the following p
roperties with transpose operators: for every pair of n-by-n complex m
atrices A and B, (a) phi preserves the spectrum of A, (b) phi(phi(A))
= A, and (c) phi(AB) = phi(B)phi(A). We show that (A, phi(A)) is contr
agrediently similar to (B, phi(B)) if and only if A = X(1)BX(2) for so
me nonsingular X(1), X(2) that satisfy X(1)(-1) = phi(X(1)) and X(2)(-
1) = phi(X(2)). We also consider a factorization of the form A = XY, w
here X(-1) = phi(X) and Y = phi(Y). We use the canonical form for the
contragredient equivalence relation to give a new proof of a theorem o
f Flanders concerning the relative sizes of the nilpotent Jordan block
s of AB and BA. We present a sufficient condition for the existence of
square roots of AB and BA and close with a canonical form for complex
orthogonal equivalence.