It is shown that Littlewood's one circle problem has a negative answer
, that is, there exists a continous bounded function f on the unit dis
k U such that f is not harmonic, but nevertheless for every x is-an-el
ement-of U the equality f(x) = 1/2pi integral-2pi/0 f(x + r(x)e(it))dt
holds for some r(x) with 0 < r(x) < 1 - parallel-to x parallel-to.