When using the maximum likelihood method to test for linkage it is tra
ditionally assumed that the female (theta(f)) and male (theta(m)) reco
mbination fractions are equal. However, this assumption is not always
realistic. In this paper we present a test for linkage that does not r
equire this assumption. Specifically, we propose testing for linkage b
y testing the null hypothesis H-0: theta(f) + theta(m) = 1 vs. the alt
ernative H-A: theta(f) + theta(m) < 1, treating theta(f) - theta(m) as
a nuisance parameter. This leads to a likelihood ratio test statistic
that is asymptotically distributed as a chi-square with one degree of
freedom. By examining the expected values of the maximum lod scores,
we show that for data from phase-known meioses this test can provide a
more powerful test for linkage-especially so when theta(f) not equal
theta(m)-unless the recombination fraction is zero. For data from phas
e-unknown meioses, the proposed test is a more powerful test for linka
ge only for large values of \theta(f)-theta(m)\; otherwise, the tradit
ional test has higher power. Thus, the proposed test can lead to gain
in power for detecting linkage when either phase is known for most mei
oses or when there is a large absolute difference between the male and
female recombination fractions. (C) 1997 Wiley-Liss.