In this note we find the exact solution for the minimal recurrence S-n = mi
n(k=1)([n/2]) {aS(n-k) + bS(k)}, where a and b are positive integers and a
greater than or equal to b. We prove that the solution is the same as that
of the recurrence relation S-n = aS(inverted right perpendicular n/2 invert
ed left perpendicular) + bS ---n/2 ---. In other words, S-n = S-1 + (a + b
- 1)S-1 Sigma(i=1)(n-1) a(z(i))b----lg n----z(i), where z(i) is the number
of zeros in the binary representaion of i. The proof follows from an intere
sting combinatorial property. With the exact solution, we can prove an opti
mal construction of certain fault tolerant circuits. (C) 2000 Elsevier Scie
nce B.V. All rights reserved.