The OH radical adds to naphthalene and naphthalene cation without a barrier
. For the neutrals, the most favorable path for this intermediate is the lo
ss of the OH, and the next most favorable option is the loss of an H atom t
o form the alcohol. For the cation, the most favorable path appears to be a
hydrogen migration followed by the loss of a hydrogen to form the alcohol.
The OH at carbon atom 1 is energetically most favorable for both the inita
l complex and final product. This is true for both the neutrals and cations
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