INTRAMOLECULAR ELECTRON-TRANSFER BETWEEN DOUBLY 4 SIGMA-BOND-LINKED TETRAALKYLHYDRAZINE CATIONIC AND NEUTRAL UNITS

Citation
Sf. Nelsen et al., INTRAMOLECULAR ELECTRON-TRANSFER BETWEEN DOUBLY 4 SIGMA-BOND-LINKED TETRAALKYLHYDRAZINE CATIONIC AND NEUTRAL UNITS, Journal of the American Chemical Society, 119(29), 1997, pp. 6863-6872
Citations number
23
Categorie Soggetti
Chemistry
ISSN journal
00027863
Volume
119
Issue
29
Year of publication
1997
Pages
6863 - 6872
Database
ISI
SICI code
0002-7863(1997)119:29<6863:IEBD4S>2.0.ZU;2-H
Abstract
Rate constants k(ESR) for intramolecular electron transfer between the reduced and oxidized hydrazine units of dimeric -3-isopropyl-2,3-diaz abicyclo[2,2.2]octylhydrazine radical cations which are doubly linked through the bicyclic units by four a-bonds (aBIT(+), sBIT(+), and aBIH (+)) were determined by simulations of their variable temperature ESR spectra in methylene chloride to be 10.5(7), 9.6(3), and 12.4(4) x 10( 7) s(-1) at 298 K, respectively. These cations show solvent sensitive charge transfer absorption bands from which the vertical electron tran sfer excitation energy, lambda, and the electronic coupling, V-J, were determined by simulation of the charge transfer bands using vibronic coupling theory (ref 13), Partitioning between solvent and vibrational components of lambda was made assuming that the average energy of the vibrational modes coupled to the electron transfer, hv(v), is 2.29 kc al/mol (800 cm(-1)). The ESR rate constants at 298 K for s- and aBIT() are factors of 23 and 26, respectively, larger than k(cal), calculat ed from lambda(s), lambda(v), h(v), and V-J estimated using a vibronic coupling theory analysis of the charge transfer bands. The ratio k(ca l)(350)/k(cal)(250) is 7.4 and 9.4(k(ESR)(350)/k(ESR)(250)) for sBIT() and aBIT(+), respectively. Previously reported data for the doubly-l inked four a-bond dimeric N,N'-bis-2,3-diazabicyclo[2.2.2]octyl hydraz ine (22H(+)) was also reanalyzed using vibronic coupling theory. k(ESR )/kcal in acetonitrile at 298 K is 20, but k(cal)(350)/k(cal)(250) is 25(k(ESR)(350)/k(ESR)(250)). Possible reasons for the rather poor agre ement with theory are suggested.